Easy difficulty hints, answers for March 4 PipsEqual (5): Everything in this space must be equal to 5. The answer is 5-5, placed horizontally.
明白了这一点，才能理解为什么30年前，香港武术指导在国际上是一块金字招牌。
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Lazy DFAs (2010) are a clever optimization to mitigate the O(2^m) blowup of DFA construction, by only constructing the states that you actually visit. lazy DFAs reduce the theoretical automata construction time to either O(2^m) or O(n), whichever is lower. you could argue that it’s theoretically no longer linear time, since you could have a regex that creates a new state for every character in the input, but in practice you will keep revisiting the same states. for all intents and purposes it behaves more like O(n) with some initial wind-up time. the main downside of lazy DFAs is that they are more complex to implement, and you have to ship a compiler as part of your regex algorithm. i want to highlight Rust regex and RE2 as excellent implementations of this approach, which you can also see in the benchmarks.
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It’s hard to disagree with those observations. I’d add a few recurring patterns:
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